-10x(x-6)=-10^+60x

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Solution for -10x(x-6)=-10^+60x equation: 



-10x(x-6)=-10^+60x

We move all terms to the left:

-10x(x-6)-(-10^+60x)=0

We multiply parentheses

-10x^2+60x-(-10^+60x)=0

We get rid of parentheses

-10x^2+60x-60x+10^=0

We add all the numbers together, and all the variables

-10x^2=0

a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-20}=0$

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